contestada

a cog company produces 20 cogs a day, 4 of which are defective. Find the probability of selecting 4 cogs from the 20 produced where none are defective?

Respuesta :

Probability of selecting a non-detective cog = 16/20

Required Probability = 16/20 * 15/19 * 14/18* 13/17 = 364/969

= 0.3756 or 37.56 % answer

=

Answer:

[tex]\bf\implies \text {Required Probbaility = }\frac{364}{969}[/tex]

Step-by-step explanation:

Number of cogs produced by the company = 20

Number of cogs which are defective = 4

no. of cogs which are not defective = 20 - 4

                                                           = 16

Now, we need to find the probability of selecting 4 cogs which are not defective

[tex]\text{Required Probability = }\frac{16}{20}\times \frac{15}{19}\times \frac{14}{18}\times\frac{13 }{17}\\\\\implies\text{Required Probability = }\frac{43680}{116280}\\\\\bf\implies \text {Required Probability = }\frac{364}{969}[/tex]