lemme do 1, 3, 5, 8 and 10, so you can see how's done, you start off by doing a prime factoring of the number.
[tex] \bf 1)
\\\\\\
\sqrt{68}~~
\begin{cases}
68=2\cdot 2\cdot 17\\
\qquad 2^2\cdot 17
\end{cases}\implies \sqrt{2^2\cdot 17}\implies 2\sqrt{17}\\\\
-------------------------------\\\\
3)
\\\\\\
\sqrt{92}~~
\begin{cases}
92=2\cdot 2\cdot 23\\
\qquad 2^2\cdot 23
\end{cases}\implies \sqrt{2^2\cdot 23}\implies 2\sqrt{23}\\\\
-------------------------------\\\\
5)
\\\\\\
\sqrt{27}~~
\begin{cases}
20=3\cdot 3\cdot 3\\
\qquad 3^2\cdot 3
\end{cases}\implies \sqrt{3^2\cdot 3}\implies 3\sqrt{3} [/tex]
[tex] \bf -------------------------------\\\\
8)
\\\\\\
\sqrt{56}~~
\begin{cases}
56=2\cdot 2\cdot 2\cdot 7\\
\qquad 2^2\cdot 2\cdot 7\\
\qquad 2^2\cdot 14
\end{cases}\implies \sqrt{2^2\cdot 14}\implies 2\sqrt{14}\\\\
-------------------------------\\\\
10)
\\\\\\
\sqrt{96}~~
\begin{cases}
96=2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 3\\
\qquad 2^2\cdot 2^2\cdot 2\cdot 3\\
\qquad (2^2)^2\cdot 2\cdot 3\\
\qquad (4)^2\cdot 6
\end{cases}\implies \sqrt{4^2\cdot 6}\implies 4\sqrt{6} [/tex]
