Respuesta :

If we use the equation:

[tex] e=\frac{c*h}{lambda} [/tex]

Where e is energy in joules, c is the speed of light which is [tex] 3.0x10^{8} [/tex] m/s, h is Planck's constant and is [tex] 6.626x10^{-34} [/tex] J/s, and lambda is wavelength in m, then we can solve for energy.

Converting wavelength from 350 nm to m, we get [tex] 3.5x10^{-7} [/tex] m.

Then we plug in the terms:

[tex] e=\frac{(3.0x10^{8} \frac{m}{s})*(6.626x10^{-34}J*s)}{3.5x10^{-7}m} [/tex]

[tex] e=5.7x10^{-19}J [/tex]

So therefore the energy of the photon is [tex] 5.7x10^{-19}J [/tex].