2C4H10 + 13O2 -----------> 8CO2 + 10H2O
Number of moles 13 mole of O2 : 8 mole of CO2
Molar ratio: n(O2) :n(CO2) = 13 : 8
n is a number of moles.
Answer : The molar ratio between the oxygen and carbon dioxide is, 13 : 8
Explanation :
The given balanced chemical reaction is :
[tex]2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O[/tex]
By the stoichiometry we conclude that, 2 moles of [tex]C_4H_{10}[/tex] react with 13 moles of [tex]O_2[/tex] to give 8 moles of [tex]CO_2[/tex] and 10 moles of [tex]H_2O[/tex] as a product.
That means,
The molar ratio between the [tex]C_4H_{10}:O_2:CO_2:H_2O[/tex] are [tex]2:13:8:10[/tex] respectively.
Thus, the molar ratio between the [tex]O_2:CO_2[/tex] is, [tex]13:8[/tex] respectively.
