A parking lot charges $3 to park a car for the first hour and $2 per hour after that. If you use more than one parking space, the second and each subsequent car will be charged 75% of what you pay to park just one car.If you park 3 cars for t hours, which function gives the total parking charge?

A. f(t) = 3(3 + 2(t − 1)) B. f(t) = (3 + 2t) + 0.75 × 2(3 + 2t) C. f(t) = (3 + 2(t − 1)) + 0.75 × 2(3 + 2(t − 1)) D. f(t) = (3 + 2t) + 0.75(3 + 2t) + 0.75 × 0.75(3 + 2t) E. f(t) = (3 + 2(t − 1)) + 0.75(3 + 2(t − 1)) + 0.75 × 0.75(3 + 2(t − 1))

Question

contestada

Respuesta :

eurydike eurydike · Answer 1 · 2018-08-08T05:43:29+02:00

Given, a parking lot charges $3 for first hour and $2 per hour after that.

So for t hours, the parking lot charges $3 for the first hour and after first hour there is [tex] (t-1) [/tex] hours left.

So for [tex] (t-1) [/tex] hours it will charge $2 per hour.

The charges for [tex] (t-1) [/tex] hours = $[tex] 2(t-1) [/tex].

Total charges for t hours for one car = $[tex] (3+2(t-1)) [/tex]

Now for the second car, it will charge 75% of the first car.

So the charges for second car

=$[ [tex] (3+2(t-1))(75/100) [/tex]]

=$[tex] 0.75(3+2(t-1)) [/tex]

There are 3 cars. That parking charges for the third car is also 75% of the first car.

So for third car the parking charges are same as for the second car.

Total parking charges for 3 cars

= $[tex] (3+2(t-1))+(0.75(3+2(t-1))+(0.75(3+2(t-1)) [/tex]

= $[tex] (3+2(t-1))+(0.75)(2(3+2(t-1)) [/tex]

We have got the required answer here.

The correct option is option C.