1) Table can be used to find the rate of change and the initial value5
x ------> y
0 -------> 3
1 ------> 5
2 ------> 7
Rate of change (Slope) = [tex] \frac{Change in y}{Change in x} [/tex]
=[tex] \frac{ 7 - 5}{2 - 1} [/tex]
= 2/1 = 2
Rate of change = 2
Y intercept is the point where x=0
So y = 3 from the table.
2) Attached the graph of a line
Rate of change = [tex] \frac{Change in y(Rise)}{Change in x} (run) [/tex]
= [tex] \frac{2}{1} [/tex] = 2
3) slope = [tex] \frac{2}{3} [/tex] and a y-intercept = 7
Equation of a line y= mx + b
Where m is the slope and b is the y intercept
Replace slope m and y intercept
m= 2/3, b= 7
Equation of a line : y = [tex] \frac{2}{3} [/tex] x + 7
4) Carson has $450 in his bank account and deposits $70 per month out of his babysitting money.
Initial amount in the bank (y intercept) b= $450
Deposited amount = 70 that is the slope m= 70
So the equation y = mx+ b , where x is the month
y = 70x + 450
Carson’s bank balance f(x) = 70x + 450
5) the graph of straight line is linear. In the graph x<1 that is (-infinity , 1) is linear.
The graph with curved line is non linear.In the graph x>1 that is (1, infinity ,) is non linear.
The graph is attached below.
