A 700-turn circular coil with an area of 0.0550 m2 is mounted on a rotating frame that turns at a rate of 16.0 rad/s in the presence of a 0.0500-t uniform magnetic field that is perpendicular to the axis of rotation. what is the instantaneous emf in the coil at the moment that the normal to its plane is at a 30.0° angle to the field?

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aristocles aristocles · Answer 1 · 2018-08-18T02:29:50+02:00

As per Faraday's law induced EMF is calculated by rate of change in flux

[tex]EMF = N\frac{d\phi}{dt}[/tex]

here magnetic flux is given by

[tex]\phi = B.A = BAcos(wt)[/tex]

here w = angular speed of rotation

now we will use above faraday's law to find induced EMF

[tex]EMF = N\frac{d(BAcoswt)}{dt}[/tex]

[tex]EMF = NBAw sin(wt)[/tex]

here

N = 700

A = 0.0550 m^2

B = 0.05 T

w = 16 rad/s

wt = 30 degree

[tex]EMF = 700* 0.0550* 0.05* 16 * sin30[/tex]

[tex]EMF = 30.8 Volts[/tex]

So induced EMF in the coil will be 30.8 Volts