Given a normal distribution with mean 120 and standard deviation 5.
We have to find number of standard deviations the measurement 134.9 is from the mean . For that we have to find z score corresponding to 134.9
The formula to find z score is
Z = [tex] \frac{x - mean}{standard deviation} [/tex]
= [tex] \frac{134.9 - 120}{5} [/tex]
= 2.98
The measurement 134.9 is 2.98 standard deviation from mean
