I'm not really good at math as you guys can tell... sorry

1) Parallelogram ABCD ---------------> Given
2) BT = TD ---------------------------------> Diagonals of a parallelogram bisect
3) <1 = <2 ----------------------------------> Vertical angles are equal
4) BC ║ AD -------------------------------> Definition of parallelogram
5) <3 = <4 ---------------------------------> If lines parallel, then alternate interior angles are equal
6) Triangle BET congruent to Triangle DFT ------>ASA
7) ET = TF ---------------------------------> CPCTE
Hope they help.
Answer:
The statements with accurate reasons are show below.
Step-by-step explanation:
Given: ABCD is a parallelogram, EF contains T.
Prove: ET=FT
1. Parallelogram ABCD (Given)
2. BT=TD (Diagonals of a parallelogram bisect each other)
3. ∠1=∠2 (Vertical angles are equal)
4. BC║AD (Definition of parallelogram)
5. ∠3=∠4 (If lines parallel, then alternate interior angles are equal)
Two corresponding angles and their included sides are congruent. So, by ASA both ΔBET and ΔD FT are congruent.
6. ΔBET ≅ ΔD FT (ASA)
7. ET=T F (CPCTE)