Respuesta :

denishin
for BE

a^2 + b^2 = c^2
5^2 + b^2 = 13^2
25 + b^2 = 169
b^2 = 144
BE= 12

and

for ED
5^2 + b^2 = sqrt 41 ^2
25 + b^2 = 41
b^2 = 16
ED = 4

BD = BE + ED
BD = 12 + 4
BD = 16

The length of BD of the kite ABCD is;

BD = 16

From the kite we can see that;

BD = BE + ED

Let us first find BE using pythagoras theorem;

BE = √(BC² - EC²)

BE = √(13² - 5²)

BE = √(169 - 25)

BE = √144

BE = 12

Similarly;

ED = √(DC² - EC²)

Where AD = DC = √41

Thus;

ED = √((√41)² - 5²)

ED = √(41 - 25)

ED = √16

ED = 4

Thus;

BD = 12 + 4

BD = 16

Read more about pythagoras theorem at; https://brainly.com/question/20545047

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