How do you do this problem?

Let area of triangle AEC = x
Area of triangle BAC = 1/2 * 15 * 12 = 90
Area of triangle DCA = 1/2 * 15 * 6 = 45
90 = p + x and
45 = q + x Subtracting the 2 equations:-
90 - 45 = p - q
Answer p - q = 45
Area of triangle ABC = 1/2 x 15 x 12 = 90
Area of triangle ACD = 1/2 x 15 x 6 = 45
Lets area of triangle ACE = x
If area of triangle ABE = p then p = 90 - x
If area of triangle CDE = q the q = 45 - x
p - q = (90 -x) - (45 - x)
p - q = = 90 - x - 45 + x
p - q = = 45
Answer
p - q = 45 square units