Respuesta :

notice the first term is -10, and the common difference is 3, so we add 3 to get the next term.

[tex] \bf \begin{array}{cccll}\stackrel{x}{n}&term&\stackrel{y}{value}\\\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\1&a_1&-10\\\\2&a_2&\stackrel{-10+3}{-7}\\\\3&a_3&\stackrel{-7+3}{-4}\\\\4&a_4&\stackrel{-4+3}{-1}\\\\5&a_5&\stackrel{-1+3}{2}\\\\6&a_6&\stackrel{2+3}{5}\end{array} [/tex]

check the picture below.

Ver imagen jdoe0001
facundo3141592

We want to graph the first 6 terms of an arithmetic sequence with a1 = -10 and d = 3.

We will see that the correct option is the first image posted.

So the general recursive formula for an arithmetic sequence is:

[tex]a_n = a_{n - 1} + d[/tex]

Using this formula we can get the other first 5 terms for the sequence, we have that:

[tex]a_2 = a_1 + d = -10 + 3 = -7\\\\a_3 = a_2 + d = -7 + 3 = -4\\\\a_4 = a_3 + d = -4 + 3 = -1\\\\a_5 = a_4 + d = -1 + 3 = 2\\\\a_6 = a_5 + d = 2 + 3 = 5[/tex]

Then we have the points:

  • (1, -10)
  • (2, -7)
  • (3, - 4)
  • (4, - 1)
  • (5, 2)
  • (6, 5)

Thus, the correct graph is the first one posted.

If you want to learn more about arithmetic sequences, you can read:

https://brainly.com/question/6561461

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