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How many grams of KMn04 would you get if you evaporated the water from 85.75 mL of 1.27 g/L solution?

Respuesta :

Willchemistry

Hey there!

Volume in liters:

85.75 mL / 1000 => 0.08575 L

Therefore:

C = m / V

1.27 = m / 0.08575

m = 1.27 * 0.08575

m = 0.1089 g

hope this helps!

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