Respuesta :
Answer:
[tex]\frac{2}{15}[/tex]
Step-by-step explanation:
An urn contains balls numbered from 1 to 15
Total number of outcomes= 15
Let E1 be event of getting a ball numbered 6
Favorable case to E1= 1
Probability=[tex]\frac{favourable case}{total number of outcomes}[/tex]
P(E1)= [tex]\frac{1}{15}[/tex]
A ball is chosen and returned to urn
Again, total number of outcomes=15
Let E2 be event of getting a ball numbered 6
Favorable case to E2= 1
P(E2)= [tex]\frac{1}{15}[/tex]
The Probability that the first and second ball is 6=P(E1)+P(E2)
=[tex]\frac{1}{15}[/tex]+[tex]\frac{1}{15}[/tex]
=[tex]\frac{2}{15}[/tex]
Hence, the correct answer is [tex]\frac{2}{15}[/tex]
