The first number is eight more than the second one. Three times the second number plus twice the first number is equal to 26. Find the numbers

Respuesta :

Let us consider the second number would be [tex] "x" [/tex]

The first number is eight more than the second one.

That is, the first number would be [tex] "x+8"
[/tex]

Three times the second number would be [tex] "3x" [/tex]

Twice the first number would be [tex] "2(x+8)" [/tex]

Now write the statement in mathematical form: "Three times the second number plus twice the first number is equal to 26"

[tex] 3x+2(x+8)= 26
[/tex]

Solve this equation for x:

Distribute 2 in [tex] x+8 [/tex], we get

[tex] 3x+2x+16=26 [/tex]

Combine the like terms,

[tex] 5x+16=26 [/tex]

Subtracting 16 on both sides,

[tex] 5x+16-16=26-16 [/tex]

[tex] 5x=10 [/tex]

Dividing 5 on both sides,

[tex] x=10/5=2 [/tex]

So the second number is [tex] x=2. [/tex]

Now find the first number:

First number [tex] = x+8=2+8=10. [/tex]

Thus the numbers are 10 and 2.