Respuesta :

bawbdmo

1.

[tex] 3d-4+d=8d+12 \implies \\4d-4=8d+12 \implies-4d=16 \implies\\ d=-4 [/tex]

2.

[tex] f-6=-2f+3(f-2) \implies \\ f-6=-2f+3f-6 \implies\\ f-6=f-6 \implies\\ 0=0 \implies \text{ all real numbers are a solution to this problem} [/tex]

mathstudent55

34. 3d - 4 + d = 8d - (-12)

3d + d - 4 = 8d + 12

4d - 4 = 8d + 12

4d - 8d - 4 + 4 = 8d - 8d + 12 + 4

-4d = 16

(-4d)/(-4) = 16/(-4)

d = -4

Answer: d = -4

35. f - 6 = -2f + 3(f - 2)

f - 6 = -2f + 3 * f - 3 * 2

f - 6 = -2f + 3f - 6

f - 6 = f - 6

f - f - 6 + 6 = f - f - 6 + 6

0 = 0

Since 0 = 0 is a true statement, that means that there is an infinite number of solutions.

Answer: The solution is all real numbers.

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