Respuesta :

Katieg3593

you would do the 75 degrees divided by 360 degrees in a circle. It equals .208 which rounds to 21%.

JeanaShupp

Answer: B)21%

Step-by-step explanation:

From the given spinner, the degrees of area covered by the stripped green section=75°

Now, the probability that the spinner arrow will land in a stripped green section (in percent) is given by ;-

[tex]\text{P(stripped green section)}=\dfrac{75^{\circ}}{360^{\circ}}\times100\\\\\Rightarrow\ \text{P(stripped green section)}=20.833333333\approx21\%[/tex]

Hence, the probability that the spinner arrow will land in a stripped green section = 21%.