we are given
diameter=84cm
so,
radius =r=42cm
height=h=120cm
we know that
shape of roller is always in cylinder form
now, we can find surface area of cylinder
[tex] SA=2\pi r h [/tex]
now, we can plug values
[tex] SA=2\pi *42*120 [/tex]
[tex] SA=31667.25395 cm^2 [/tex]
we know that
In one rotation , it covers area is 31667.25395 cm^2
There are 500 rotation
so, total area =[tex] 500*31667.25395 cm^2 [/tex]
total area =[tex] 15833626.975 cm^2 [/tex]
now, we need to change that area into m^2
we know that
[tex] 1cm^2=\frac{1}{10000} m^2 [/tex]
now, we can multiply both sides 15833626.975
we get
[tex] 15833626.975cm^2=15833626.975*\frac{1}{10000} m^2 [/tex]
[tex] 15833626.975cm^2=1583.36270 m^2 [/tex]
so,
Area of playground is [tex] 1583.36270 m^2 [/tex].............Answer
