contestada

Suppose a vehicle travels 150 km at a speed of 30.0 m/s, and uses 3.0 gal of gasoline. only 30% of the gasoline goes into useful work by the force that keeps the car moving at constant speed despite friction. if the energy content of the fuel is 1.2 x 108 j/gal. what is the magnitude of the force exerted to keep the car moving at constant speed?

Respuesta :

Only 30% of gasoline is used for useful work in that engine

Now it is given that 3 Gal gasoline is used in the car

So the actual gasoline used by engine will be

[tex] Q = 0.30 * 3 = 0.9 Gal[/tex]

energy content of gasoline will be

[tex]E = 1.2 * 10^8 J/gal[/tex]

Energy consumed by the engine will be given by

[tex]E = 1.2 * 10^8 * 0.9 = 1.08 * 10^8 J[/tex]

now let say engine applied F force against the air drag to move the car

So work done by the engine = energy consumed by it

[tex]W = F*d[/tex]

[tex]1.08 * 10^8 = F * 150*10^3[/tex]

[tex]1.08 * 10^8 = F* 1.50* 10^5[/tex]

[tex]F = \frac{1.08* 10^8}{1.50* 10^5}[/tex]

[tex]F = 720 N[/tex]

so engine must have to apply 720 N force

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