Question 1(Multiple Choice Worth 4 points) (08.06) What are the factors of x2 − 64? Prime

(x − 4)(x + 16)

(x − 8)(x − 8)

(x + 8)(x − 8)

Question 2(Multiple Choice Worth 4 points) (08.05) Identify the factors of 4x2 + 20x + 25.

(4x + 5)(x + 5)

(4x − 5)(x − 5)

(2x + 5)(2x + 5)

(2x − 5)(2x − 5)


Question 3(Multiple Choice Worth 4 points) (08.03) Determine the factors of 5x2 + 29x − 6.

(5x − 1)(x + 6)

(5x − 6)(x + 1)

(5x − 3)(x + 2)

(5x − 2)(x + 3)



Question 4(Multiple Choice Worth 4 points) (08.07) A polynomial function can be written as (x − 1)(x − 4)(x + 7). What are the x-intercepts of the graph of this function? (1, 0), (4, 0), (7, 0)

(−1, 0), (−4, 0), (−7, 0)

(1, 0), (4, 0), (−7, 0)

(−1, 0), (−4, 0), (7, 0)


Question 5(Multiple Choice Worth 4 points) (08.03) What

Respuesta :

Question 2:

What are the factors of x² − 64?

let us first find square root of 64, which is 8

so writing x² − 64 as x² − 8²

Now we use the identity

a²-b² = (a+b)(a-b)

x²-8² = (x+8)(x-8)

So answer is option C. (x+8)(x-8)

Question 2:

Identify the factors of 4x² + 20x + 25.

Using AC method , we first multiply 4*25 =100

finding factors of 100 that add up to give 20 we have 10 and 10.

4x² + 10x+10x + 25

factoring by grouping we have,

(2x+5)(2x+5)

Option C is correct.

Question 3:

Determine the factors of 5x² + 29x − 6.

Using AC method, multiplying 5(-6) = -30, finding two factors of -30 that add up to give 29 are 30 and -1.

5x² + 30x-x − 6

factoring by grouping we get

(x+6)(5x-1)

option 1) is correct.

Question 4:

A polynomial function can be written as (x − 1)(x − 4)(x + 7). What are the x-intercepts of the graph of this function?

equating each product equal to zero,

(x-1) =0 , x=1

(x-4)=0, x=4

x+7=0, x=-7

so zeros are (1,0) , (4,0) and (-7,0).

Option C is correct.