Given:
[tex] \triangle v [/tex] = 12 m/s
Time = 15 s
To find:
Deceleration = ?
Formula used:
Deceleration is given by,
a = [tex] \frac{\triangle v}{t} [/tex]
Solution:
Acceleration of the body is rate of increase of velocity. Deceleration of the body is negative acceleration i. e rate of decrease of velocity.
Thus, deceleration of the body is given by,
a = [tex] \frac{\triangle v}{t} [/tex]
where a is the deceleration of the body
v is the velocity
[tex] \frac{\triangle v}{t} [/tex] is rate of change of velocity
t is the time
a = [tex] \frac{12}{15} [/tex]
a = 0.8 m/ [tex] s^{2} [/tex]
Thus, deceleration is 0.8 m/ [tex] s^{2} [/tex].
