The given thermochemical equation is:
[tex] 2 CO (g) + O_{2}(g) --->2CO_{2}(g) [/tex] Δ[tex] H^{0} = -482 kJ/mol [/tex]
Mass of CO given = 24.0 g
Moles of CO = [tex] 24.0 g CO * \frac{1 mol CO}{28 g CO} = 0.857 mol CO [/tex]
Finding out the heat released to the surroundings when 24.0 g CO:
[tex] 0.857 mol CO * \frac{482 kJ}{2 mol CO} = 207 kJ [/tex]
Therefore, 207 kJ of heat is released to the surroundings when 24.0 g CO reacts completely.
