Answer : The [tex]H_3O^+[/tex] concentration and the pH of the solution is, [tex]1\times 10^{-9}M[/tex] and 9 respectively.
Explanation:
First we have to calculate the pOH.
[tex]pOH=-\log [OH^-][/tex]
[tex]pOH=-\log (1\times 10^{-5})[/tex]
[tex]pOH=5[/tex]
Now we have to calculate the pH.
[tex]pH+pOH=14\\\\pH=14-pOH\\\\pH=14-5=9[/tex]
Now we have to calculate the [tex]H_3O^+[/tex] concentration.
[tex]pH=-\log [H_3O^+][/tex]
[tex]9=-\log [H_3O^+][/tex]
[tex][H_3O^+]=1\times 10^{-9}M[/tex]
Therefore, the [tex]H_3O^+[/tex] concentration and the pH of the solution is, [tex]1\times 10^{-9}M[/tex] and 9 respectively.
