The given balanced chemical equation:
[tex] CaCO_{3}(s) +2 HCl (aq) --> CaCl_{2}(aq)+H_{2}O(l) + CO_{2}(g) [/tex]
Calculating the moles of carbon-dioxide:
Given, moles of [tex] CaCO_{3} = 0.00500 mol CaCO_{3} [/tex]
Moles of [tex] CO_{2} = 0.00500 mol CaCO_{3} * \frac{1 mol CO_{2}}{1 mol CaCO_{3}} [/tex]
[tex] = 0.00500 mol CO_{2} [/tex]
Using the ideal gas equation to find out volume from moles, pressure and temperature:
PV = nRT
[tex] P is the pressure = 100 kPa *\frac{1 atm}{101.325 kPa} = 0.987 atm [/tex]
[tex] T is the temperature = 25^{0}C + 273 = 298 K [/tex]
[tex] (0.987 atm)(V) = (0.00500 mol)(0.08206 \frac{L.atm}{(mol.K)}(298K) [/tex]
V = 0.124 L or 124 mL
Therefore, 124 mL of carbon dioxide will be collected.