Exposerer
contestada

In a quadrilateral MNOP the length of side MN is (4x − 7) units and the length of side ON is (7 − 3x) units. What value of x will make it a rhombus?

14
2
7
12

Respuesta :

Riia

In a rhombus, all sides are equal.

So for the quadrilateral MNOP to be a rhombus, the given sides have to be equal. THat is

[tex] MN=ON [/tex]

[tex] 4x-7 =7-3x
[/tex]

Adding 3x to both sides and addinf 7 to both sides

[tex] 7x = 14 [/tex]

Now we need to get rid of 7 and for that we do division, that is

[tex] \frac{7x}{7} = \frac{14}{7} [/tex]

[tex] x=2 [/tex]

Correct option is the second option .

Otras preguntas