Hello!
In the first quadrant, all the trigonometric functions are positive.
In the second quadrant, sin and csc are positive, the rest are negative.
In the third quadrant, tan and cot are positive; the rest are negative.
In the fourth quadrant, cos and sec are positive, and the rest are negative.
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To find sin 2θ, we use the equation: sin 2θ = 2 sinθ cosθ.
Since we are given cos θ, which is 3/5, we need to find sin θ.
cos θ = x / r
sin θ = y / r
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To find y, we need to use the Pythagorean Theorem.
3² + y² = 5²
9 + y² = 25 (subtract 9 from both sides)
y² = 16 (take the square root of both sides)
y = 4
Since sin θ is negative in quadrant 4, the y-value of sin θ is negative.
Therefore, sin θ = -4/5.
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Then, we can substitute these values into sin 2θ = 2sinθ cosθ
sin 2θ = 2(-4/5)(3/5)
sin 2θ = (-8/5)(3/5)
sin 2θ = -24/25
Therefore, sin 2 theta is equal to -24/25.
The value of sin2 theta is in the 4th quadrant is -24/25
Given the expression of cos theta = 3/5 with theta in quadrant 4;
According to SOH, CAH TOA;
cos theta = adjacent/hypotenuse
Get the opposite
5² = opp² + 3²
opp² = 25 - 9
opp² = 16
opp = 4
Sin theta = opp/hyp
Sin theta = 4/5
Sin2 theta = 2sintheta cos theta
Sin2theta = 2(-4/5)(3/5)
Sin2theta = -24/25
Hence the value of sin2 theta is in the 4th quadrant is -24/25
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