[tex] \bf \cfrac{3x-6}{x-2}\implies \cfrac{3(\underline{x-2})}{\underline{x-2}}\implies 3 [/tex]
So we have the equation:
[tex] \frac{3x-6}{x-2} [/tex]
Then we can talk out a common factor of 3 in the numerator:
[tex] \frac{3(x-2)}{x-2} [/tex]
Since we have the term (x - 2) in both the numerator and the denominator (and in the numerator this term is being multiplied), we are able to cancel out these terms.
Therefore, the final answer is 3.