10-08-2018
Mathematics

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Xavier's bowling average is 185.4 and Lola's average is 122.9. About how many times greater is Xavier's average than Lola's?

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Аноним Аноним

10-08-2018

Hello!

To find how many times greater his average is, we just divide.

185.4/122.9≈1.51

Therefore, his average is about 1.51 times greater than Lola's.

I hope this helps!

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matthavan matthavan

10-08-2018

Hi. It is 62.5 times greater

Ver imagen matthavan

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