Respuesta :

Exvited
[tex]6a^2 - 23a - 4 \\ \\ 6a^2 + a - 24a - 4 \\ \\ a(6a + 1) - 4(6a + 1) \\ \\ (6a + 1)(a - 4) \\ \\ [/tex]

The final result is: (6a + 1)(a - 4).

So yes, you are correct.
TSO
[tex]6a^2 - 23a - 4[/tex]

Two numbers must add to -23 and multiply to -24

Those two numbers would be: -24 and 1

So, now, let's split the middle term into -24a + 1a

[tex]6a^2 - 23a - 4=\\\\6a^2 - 24a+1a - 4[/tex]

Now, let's factor by grouping. :)

[tex]6a^2 -24a + 1a - 4 =\\\\(6a^2 -24a)(+1a-4)=\\\\6a(a-4)+1(a-4)=\\\\\boxed{\bf{(a-4)(6a+1)}}\\\\\\\boxed{\bf{6a^2 - 23a - 4 = (6a + 1)(a - 4)}}[/tex]

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