the initial population of a town is 3300
after 10 years: 3300 + 3300*(10/10) = 6600
after 12 years: 6600 + 6600*(2/10) = 7920
Answer:
5746
Step-by-step explanation:
Given that the initial population of a town is 3900, and it grows with a doubling time of 10 years.
i.e. population grows exponentially as
[tex]P(t) = 3900 (2)^{\frac{t}{10} }[/tex]
Using this we can calculate population for 8 years
P(8) = [tex]3900(2)^{\frac{8}{10} } \\=5745.63\\~5746[/tex]
Population in 8 years is 5746