Respuesta :
The garden's width is 45. We know this because
[tex]35 \times 2[/tex]
(length)
[tex]35 \times 2 + 2x = 160 \\ [/tex]
35x2 is 70 and you need to neutralize that by taking away 70 from both sides.
[tex]160 - 70 = 90[/tex]
[tex]2x = 90[/tex]
Now divide by 2 on both sides to neutralize the 2 times x.
[tex]90 \div 2 = 45[/tex]
meaning that leaves us with
[tex]x = 45[/tex]
[tex]35 \times 2[/tex]
(length)
[tex]35 \times 2 + 2x = 160 \\ [/tex]
35x2 is 70 and you need to neutralize that by taking away 70 from both sides.
[tex]160 - 70 = 90[/tex]
[tex]2x = 90[/tex]
Now divide by 2 on both sides to neutralize the 2 times x.
[tex]90 \div 2 = 45[/tex]
meaning that leaves us with
[tex]x = 45[/tex]
Answer:
[tex]2(35+w)=160[/tex]
Step-by-step explanation:
Let w represent width of the garden.
We know that perimeter of rectangle is [tex]2(\text{Length}+\text{Width})[/tex].
We have been given that the length of the garden is 35 feet, and the total fencing used to enclose the garden measures 160 feet.
We can set this information in an equation as:
[tex]2(35+w)=160[/tex]
Therefore, the equation can be used to find the width of the garden.
[tex]\frac{2(35+w)}{2}=\frac{160}{2}[/tex]
[tex]35+w=80[/tex]
[tex]35-35+w=80-35[/tex]
[tex]w=45[/tex]
Therefore, the width of garden is 45 feet.
