For this case we have the following function:
[tex] h (x) = - 3 (x-3) ^ 2 + 108 [/tex]
By the time of the landing we have:
[tex] -3 (x-3) ^ 2 + 108 = 0 [/tex]
From here, we clear the value of x.
We have then:
[tex] -3 (x-3) ^ 2 = -108 [/tex]
[tex] (x-3) ^ 2 = \frac{-108}{- 3} [/tex]
[tex] (x-3) ^ 2 = 36 [/tex]
Discarding the negative root we have:
[tex] (x-3) = \sqrt{36} [/tex]
[tex] x = 6 + 3 [/tex]
[tex] x = 9 [/tex]
Answer:
9 seconds after takeoff the hovercraft will land on the ground
Answer:
9 Seconds
Step-by-step explanation:
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