A sample of tennantite with mass of 2370 g contains 19.23 mol Cu.
You must make the following conversions:
Mass of tennantite → moles of tennantite → moles of Cu
Step 1. Calculate the moles of tennantite (Tn)
The ideal chemical formula of Tn is Cu_12As_4S_13.
Molar mass = (12×63.55 + 4×74.92 + 13×32.06) g/mol
= (762.60 + 299.68 + 416.78) g/mol = 1479.06 g/mol
Moles of Tn = 2370 g Tn × (1 mol Tn/1479.06 g Tn) = 1.60 24 mol Tn
Step 2. Calculate the moles of Cu
Moles of Cu = 1.6024 mol Tn × (12 mol Cu/1 mol Tn) = 19.23 mol Cu
19.224 moles of copper are present in a sample of tennantite with a mass of 2370 grams.
Explanation:
The tennantite is a mineral of copper, arsenic, and sulfur.
The ideal chemical formula of tennantite = [tex]Cu_{12}As_{4}S{13}[/tex]
Given :
The sample of 2,370 grams of tennantite.
To find:
The number of moles of copper in 2370 grams of tennantite.
Solution:
The mass of tennantite = 2,370 g
The molar mass of tennantite :
[tex]=12\times 63.55 g/mol+4\times 74.92g/mol+13\times 32.06 g/mol=1,479.06 g/mol[/tex]
The moles of tennantite :
[tex]=\frac{2,370 g}{1,479.06 g/mol}=1.602 mol[/tex]
In 1 mole of tennantite, there are 12 moles of copper, then in 1.602 moles of tennantite there will be:
[tex]=12\times 1.602 mol=19.224 mol[/tex]
19.224 moles of copper are present in a sample of tennantite with a mass of 2370 grams.
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