Total time of flight of rat to go up in the air and again come back on the lap is given as
[tex]T = 3 s[/tex]
Part a)
This time of flight depends on the initial speed and acceleration due to gravity
So by kinematics we can say
[tex]T = \frac{2v}{g}[/tex]
[tex]3 = \frac{2v}{9.8}[/tex]
[tex]v = 14.7 m/s[/tex]
Now in order to find the maximum height we can use
[tex]v_f^2 - v_i^2 = 2 a d[/tex]
here final speed is zero and acceleration is due to gravity
[tex]0 - v^2 = 2*(-g)*H[/tex]
by rearranging above equation we have
[tex]H = \frac{v^2}{2g}[/tex]
[tex]H = \frac{14.7^2}{2*9.8}[/tex]
[tex]H = 11.025 m[/tex]
so it will move up to height 11.025 m
