The dimensions of aluminum foil in a box for sale in super markets are 66 2/3 yards by 12 inches. the mass of the foil is 0.83 kg. if its density is 2.70 g/cm3 , then what is the thickness of the foil in inches?

Respuesta :

Length of the sheet is given as

[tex]L = \frac{200}{3} yards = 6096 cm[/tex]

width of the sheet is given as

[tex]w = 12 inches = 30.48 cm[/tex]

now let say its thickness is "t"

so the volume of the sheet is given as

[tex]V = L*w*t[/tex]

[tex]V = 6096*30.48* t[/tex]

[tex]V = 185806.08*t cm^3[/tex]

mass of the sheet is given as

[tex]m = 0.83 kg = 830 gram[/tex]

now we have

[tex]density = \frac{mass}{volume}[/tex]

[tex]2.70 = \frac{830}{185806.08*t}[/tex]

by solving above we have

[tex]t = 1.65 * 10^{-3} cm[/tex]

so the thickness of sheet will be above