A rectangle is 12 feet long and five feet wide.if the length of the rectangle is increased by 25% and the width is decreased by 20%, what is the change in the area of the rectangle

Respuesta :

First of all, let's single out the 12 feet long and the 5 feet wide. We need to figure out what 25% of the length (12 feet) is. Let's divide 12 by 4. We get 3. Now, let's remember that.


Second, we need to figure out what 20% of the width (5 feet) is. Let's divide 5 by 5. We get 1. Now, let's also remember that number.


Now, we must add the numbers we got to the original length and width. For 12, we got 3, and 12+3=15. For 5, we got 1, and 5+1=6.


Now that we have the new length (15) and the new width (6), we must multiply to find the new area. 15x6=90. Using the original length (12) and the original width (5) we will multiply to find the original area. 12x5=60.


Original Area: 60 feet.

Area after increasing length and width: 90 feet.

Change in area: 30 feet.


I hope this explanation helped you out so that you can do it yourself next time. If you need anymore help, feel free to message me.

First we need to find out what 25% of 12 is and what 20% of 5 is.

12 x .25 = 3     and     5 x .20 = 1

Now that that is out of the way we need to add the 3 to the twelve because the length increasing. And we need to subtract the 1 from the 5 because the width is decreasing.

12 + 3 = 15     and     5 - 1 = 4

Once you've done that, you now have the new length and width of your rectangle. To get the square foot of the new rectangle, you multiply 15 by 4.

15 x 4 = 60