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A man located at a point a on one bank of a river that is 1000 ft wide observed a woman jogging on the opposite bank. when the jogger was first spotted, the angle between the river bank and the man's line of sight was 25°. one minute later, the angle was 35°. how fast was the woman running if she maintained a constant speed? (round your answer to the nearest integer.)

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Blacklash

Refer the given figure

Here A is the position of observer and B1 is the first position of lady and B2 is the position after one minute.

The distance traveled by lady = B1B2 = AC1 - AC2

We have AC1 = 1000[tex]cot25^0[/tex] = 2144.51 m

               AC2 = 1000[tex]cot35^0[/tex] = 1428.15 m

The distance traveled by lady = B1B2 = AC1 - AC2 = 2144.51 - 1428.15 = 716.36 m

So velocity of lady = distance / time = 716.36/60 = 11.94 m/s ≈ 12 m/s

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