[tex] \\ \text{We know that the point-slope for the line passing throught }(x_1, y_1)\\ \text{and having slope m is given by}\\ \\ y-y_1=m(x-x_1)\\ \\ \text{so using this point-slope form of line, the equation of the line passing}\\ \text{through the point }(6,-1)\text{ and having a slope of }m=2\text{ is}\\ \\ y-(-1)=2(x-6)\\ \\ \Rightarrow y+1=2(x-6)\\ \\ \text{this is the required point-slope form of the line.} [/tex]
y+1 =2 (x-6)
Answer:
[tex]y+1=2(x-6)[/tex]
Step-by-step explanation:
The slope of the line is 2. Hence, m = 2
And it passes through the point (6,-1). Hence, [tex]x_1=6,y_1=-1[/tex]
The point slope form of the line is given by the equation
[tex]y-y_1=m(x-x_1)[/tex]
Substituting the known values, we get
[tex]y-(-1)=2(x-6)[/tex]
On simplifying, we get
[tex]y+1=2(x-6)[/tex]
Therefore, the point slope form of the line is [tex]y+1=2(x-6)[/tex]
