Respuesta :

((3^8)(2^−5)(9^0))^−2(2^−2/3^3)^4(3^28)

=(6561(2^−5)(9^0))^−2(2^−2/3^3)^4(3^28)

=(6561(1/32)(90))^−2(2^−2/3^3)^4(3^28)

=(6561/32(9^0))^−2(2^−2/3^3)^4(3^28)

=(6561/32(1))^−2(2^−2/3^3)^4(3^28)

=(6561/32)^−2(2^−2/3^3)^4(3^28)

=1024/43046721(2^−2/3^3)^4(3^28)

=1024/43046721(2^−2/3^3)^4(3^28)

=(1024/43046721(1/4/27))^4)(3^28)

=(1024/43046721(1/108)^4)(3^28)

4/22876792454961  (22876792454961)=4

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Note that when there is a number with power inside the parenthesis, and a power sign outside the parenthesis, you must multiply

(3^8)^-2 = 3^-16

(2^-5)^-2 = 2^10

(9^0)^-2 = 9^0

Simplify

3^-16 = 1/43,046,721

2^10 = 1024

9^0 = 1

Multiply

1/43,046,721  x 1024 = 1024/43046721 = 0.0000237881

0.0000237881 = 2.37881 x 10^-5

Answer are bolded. Not sure which one you want.

hope this helps

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