The surface area of a swimming pool is 210 square feet. What is the length d of the deep end (in feet)?

[tex]\bf \textit{area of a rectangle}\\\\ A=Lw~~ \begin{cases} L=length\\ w=width\\[-0.5em] \hrulefill\\ A=210\\ w=10\\ L=d+9 \end{cases}\implies 210=(d+9)(10)\implies \cfrac{210}{10}=d+9 \\\\\\ 21=d+9\implies 12=d[/tex]
The length d of the deep end is 12 feet
Surface area is the total sum of all the faces of an object. The swimming pool is rectangular in nature.
Area of its surface = LW
L is the length
W is the width
Given the following
Area = 210 square feet
Length = 10 feet
Width = (d+9)feet
Substitute into the formula:
210 = 10(d+9)
210 = 10d + 90
10d = 210 - 90
10d = 120
d = 120/10
d = 12feet
Hence the length d of the deep end is 12 feet
Learn more here: https://brainly.com/question/17229451