kp2004
contestada

Find the point, M, that is five-sixths of the distance from A(-7, 2) to B(-1, -4).
A) (-1, -3)
B) (-2, -3)
C) (-1, -4)
D) (-2, -4)

Respuesta :

Firstly, how many units apart is -7 from -1 (the x-coordinates)? That would be 6 units away. Multiply 5/6 by 6:

[tex]\frac{5}{6}\times \frac{6}{1}=\frac{30}{6}=5[/tex]

Next, how many units apart is 2 from -4? That would be, again, 6 units. Multiply 5/6 by 6.

[tex]\frac{5}{6}\times \frac{6}{1}=\frac{30}{6}=5[/tex]

Now, since from -7 to -1 it's increasing, add 5 to -7:

[tex]-7+5=-2[/tex]

-2 is the x-coordinate of M.

Next, since from 2 to -4 it's decreasing, subtract 5 from 2:

[tex]2-5=-3[/tex]

-3 is the y-coordinate of M.

Putting it together, M is at (-2,-3), or B.

Answer(-2,-3)

Step-by-step explanation:

(-2, -3) The coordinates of M are (xm, ym), where xm = -7 +  

5

11

(-1 - (-7)) and ym = 2 +  

5

11

(-4 - 2).