It is given in the question that
y varies inversely as x^2 and y = 3 when x = 18.
SInce y varies inversely as square of x, so the formula will be
[tex]y = \frac{k}{x^2}[/tex]
Where k is the constant of proportionality .
Substituting the values of y and x, we will get
[tex]3 = \frac{k}{18^2}[/tex]
[tex]3 = \frac{k}{324}[/tex]
Multiplying both sides by 324,
[tex]k = 972[/tex]
So the equation will be
[tex]y= \frac{972}{x^2}[/tex]
And when x equals 3, we will get
[tex]y = \frac{972}{9} = 108[/tex]
Therefore the correct option is B .
