Answer:
The answer is option B : 78.
Step-by-step explanation:
A warehouse has 518 flash drives on hand.
The warehouse manager decides to keep 50 flash drives for high-priority orders and fill six equal-size orders with the rest of the flash drives.
So, remaining flash drives are = [tex]518-50=468[/tex]
As there are 6 equal-size orders, so there will be [tex]\frac{468}{6}= 78[/tex] flash drives in each box.
Therefore, the answer is option B : 78.
