(a) winnie first approximated each distance to the nearest hundredth.
[tex]\sqrt{60} =7.75[/tex]
[tex]\frac{58}{8} = 7.25[/tex]
7.3 = 7.33
[tex]7\frac{3}{5} = 7.60[/tex]
Now we find the average of 4 numbers
[tex]\frac{7.75+7.25+7.33+7.60}{4}[/tex]= [tex]\frac{29.93}{4} = 7.4825[/tex]
Winnie's estimate = 7.4825
B) Winnie's father estimated the distance across his ranch to be the square root of 56 km
[tex]\sqrt{56} = 7.48331[/tex]
Winne's father estimate - Winne's estimate = 7.48331 - 7.48225= 0.00106
Winne's father estimate is 0.00106 more than winne's estimate
