Length (L): x ⇒ 5
width (w): 5x³ - 4x² ⇒ 5(5)³ - 4(5)² = 625 - 100 = 525
Perimeter (P) = 2L + 2w
P = 2(5) + 2(525)
= 10 + 1050
= 1060
Answer: 1060 feet
Answer:
1060 feet.
Step-by-step explanation:
We have been given that a rectangle has a length of x and a width of [tex]5x^3-4x^2[/tex]. We are asked to find the perimeter of rectangle when the length is 5 feet.
We know that perimeter of rectangle is two times the sum of length and width of rectangle.
[tex]\text{Perimeter}=2(l+w)[/tex]
[tex]\text{Perimeter}=2(x+5x^3-4x^2)[/tex]
Upon substituting [tex]x=5[/tex], we will get:
[tex]\text{Perimeter}=2(5+5(5)^3-4(5)^2)[/tex]
[tex]\text{Perimeter}=2(5+5*125-4*25)[/tex]
[tex]\text{Perimeter}=2(5+625-100)[/tex]
[tex]\text{Perimeter}=2(630-100)[/tex]
[tex]\text{Perimeter}=2(530)[/tex]
[tex]\text{Perimeter}=1060[/tex]
Therefore, the perimeter of the rectangle is 1060 feet.
