Answer:
3.03 g
Solution:
Data Given:
Molarity = 0.50 mol.L⁻¹
M.Mass = 121.1 g.mol⁻¹
Volume = 50 mL = 0.05 L
Step 1: Calculate moles as,
Molarity = Moles ÷ Volume
Solving for Moles,
Moles = Molarity × Volume
Putting values,
Moles = 0.50 mol.L⁻¹ × 0.05 L
Moles = 0.025 mol
Step 2: Calculate Mass of Tris as,
Moles = Mass ÷ M.Mass
Solving for Mass,
Mass = Moles × M.Mass
Putting values,
Mass = 0.025 mol × 121.1 g.mol⁻¹
Mass = 3.03 g
