Respuesta :

Aaryan00
let the consecutive odd numbers be:
x, x+2, x+4

given that: (x)(x+2)(x+4)=2145

on solving we get x=11 (comment if you want to know the full method to solve)

so the three numbers are:
11, 13, 15

The expressions for finding the numbers is x³ + 6x² + 8x - 2145 = 0

The numbers are 11, 13 and 15.

The 3 numbers are consecutive and are odd number.

Therefore,

let

the first odd number = x

The next ones will be as follows:

x, x+2, x + 4

x(x + 2)(x + 4) = 2145

x(x² + 4x + 2x + 8) = 2145

x(x² + 6x + 8) = 2145

x³ + 6x² + 8x = 2145

x³ + 6x² + 8x - 2145 = 0

inserting x = 11 we will get zero

Therefore,

x = 11

The next numbers are 13 and 15

read more: https://brainly.com/question/12420213

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