Answer: 1.98\times10^{-13}m[/tex]
We need to find the wavelength of the deutrons which are travelling with a velocity of [tex]1\times10^6m/s[/tex]. we would use de-Broglie's formula which relates momentum of the particle with its wavelength.
[tex]\lambda=\frac{h}{mv}[/tex]
where, h = Planck's constant
m is the mass
v is the velocity
and [tex]\lambda[/tex] is the wavelength.
Deutron has 1 neutron and 1 proton.
Mass of deutron is [tex]2\times 1.67\times10^{-27} kg=3.34\times10^{-27} kg[/tex] (because of mass of proton =mass of neutron = [tex]1.67\times10^{-27}kg[/tex]
[tex]\Rightarrow \lambda=\frac{6.626\times10^{-34}J.s}{3.34\times10^{-27}kg\times10^6m/s}=1.98\times10^{-13}m[/tex]
Therefore, the wavelength of the deutrons travelling with the speed [tex]10^6 m/s[/tex] is [tex]1.98\times10^{-13}m[/tex]
Answer: 2×10⁻¹³ m
Explanation:
1) Data:
2) Formula
λ = h/(m×v)
Where h is the Planck constant, h = 6.626×10⁻³⁴ J s
3) Solution:
b) wavelength
