Answer is: 3.011·10²³ molecules of glycerol.
c(C₃H₈O₃) = 0.5 M; concentration of glycerol solution.
V(C₃H₈O₃) = 1 L; volume of glycerol.
M(C₃H₈O₃) = 92 g/mol; molecular mass of glycerol.
n(C₃H₈O₃) = c(C₃H₈O₃) · V(C₃H₈O₃),
n(C₃H₈O₃) = 0.5 M · 1 L.
n(C₃H₈O₃) = 0.5 mol, amount of substance.
N(C₃H₈O₃) = n(C₃H₈O₃) · Na(Avogadro constant).
N(C₃H₈O₃) = 0.5 mol · 6.022·10²³ 1/mol.
N(C₃H₈O₃) = 3.011·10²³.
