Respuesta :
As we know that when charge is released in electric field
It will have two forces on it
1. electrostatic force
2. gravitational force
now if the ball will accelerate upwards so we can say
net upward force = mass * acceleration
[tex]qE - mg = ma[/tex]
[tex]q*200000 - 1.9 * 10^{-3}* 9.8 = 1.9 * 10^{-3}* 15[/tex]
now we can find charge q on it by above equation
[tex]q = 0.2356 * 10^{-6} C[/tex]
So above is the charge on the particle
The charges on the bead having a mass of 1.9 g are held in a uniform electric field is 2.3569x10⁻⁷ C.
What is the charge on the bead?
We know that since the bead is accelerating upwards there will be two forces that will act on the bead, a resisting force that will try to drag the bead down(gravitational force) and an upward electrostatic force.
Therefore,
Electrostatic force - gravitational force = m x a
[tex]\overrightarrow Eq - m\cdot g = m \cdot a\\[/tex]
Given to us the following values,
m = 1.9 g = 0.0019 kg
g = 9.81 m/s²
a = 15 m/s²
[tex]\overrightarrow E[/tex] = 200,000 N/C
Substitute all the values,
[tex]\overrightarrow Eq - m\cdot g = m \cdot a\\\\(200000)q - (0.0019 \times 9.81) = (0.0019 \times 15)\\\\(200000)q -(0.018639)= (0.0285)\\\\(200000)q=0.047139\\\\q = 2.3569 \times 10^{-7}\ C[/tex]
Hence, the charge on the bead having a mass of 1.9 g is held in a uniform electric field is 2.3569x10⁻⁷ C.
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